Abstract
The arithmetic-geometric mean inequality for singular values due to Bhatia and Kittaneh says that 2sj(AB*) ≤ sj(A*A + B*B), j = 1, 2, ... for any matrices A, B. We first give new proofs of this inequality and its equivalent form. Then we use it to prove the following trace inequality: let A0 be a positive definite matrix and A 1,..., Ak be positive semidefinite matrices. Then tr ∑j=1k (∑i=0jA i-2) Aj < tr A0-1.
| Original language | English |
|---|---|
| Pages (from-to) | 299-303 |
| Number of pages | 5 |
| Journal | Linear Algebra and Its Applications |
| Volume | 376 |
| Issue number | 1-3 |
| DOIs | |
| State | Published - 1 Jan 2004 |
Keywords
- Norm
- Singular value
- Trace inequalities