Abstract
In this paper, using a recent result of Bilu, Hanrot and Voutier on primitive divisors, we prove that if a = |Vr|, b = |Ur|, c = m2 + 1, and b ≡ 3 (mod 4) is a prime power, then the Diophantine equation x2 + by = cz has only the positive integer solution (x,y, z) = (a, 2, r), where r > 1 is an odd integer, m ∈ N with 2 | m and the integers Ur, Vr satisfy (m + √-1)r = Vr + Ur√-1.
| Original language | English |
|---|---|
| Pages (from-to) | 199-202 |
| Number of pages | 4 |
| Journal | Proceedings of the Japan Academy Series A: Mathematical Sciences |
| Volume | 78 |
| Issue number | 10 |
| DOIs | |
| State | Published - Dec 2002 |
| Externally published | Yes |
Keywords
- Exponential Diophantine equation
- Gauss integer
- Lucas sequence
- Primitive divisor